(4/x+5)+(2/x-5)=(32/x^2-25)

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Solution for (4/x+5)+(2/x-5)=(32/x^2-25) equation: 



(4/x+5)+(2/x-5)=(32/x^2-25)

We move all terms to the left:

(4/x+5)+(2/x-5)-((32/x^2-25))=0



Domain of the equation: x+5)!=0

x∈R





Domain of the equation: x-5)!=0

x∈R





Domain of the equation: x^2-25))!=0

x∈R



We get rid of parentheses

4/x+2/x-((32/x^2-25))+5-5=0

We calculate fractions

We do not support expression: x^3

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